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Disusun oleh:. Arvin Primo Bhakti Nuryadin Bhre Kumara Hangga W. Dwi Agus Sulistia Deni Agus Iriyanto Dimas Izuladha Fariza Indriyanto Fiska Suhenda Fachriza Sofyan Freddy Satriyo Fuad Barlian Giant Hermawan Hilman Alfian Indra Putra Temagangka Indra Setiawan Insan Fadilah.
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Disusun oleh: Arvin Primo Bhakti Nuryadin Bhre Kumara Hangga W. Dwi Agus Sulistia Deni Agus Iriyanto Dimas Izuladha Fariza Indriyanto Fiska Suhenda Fachriza Sofyan Freddy Satriyo Fuad Barlian Giant Hermawan Hilman Alfian Indra Putra Temagangka Indra Setiawan Insan Fadilah istem Control Pada DC Motor Speed
DC Motor DC Motor Speed • Komponen Utama • Magnit • Kumparan • Arus DC • Input :Voltase • Output :Putaran
Ef = Lf ea ef k1 eb k4 Lf Rf ea ef La Ra ea = konstan Tm DC Motor Speed Modeling 5. eb = k3 . ω Persamaannya: ea = k4 . r ef = k1(ea – eb) ef = Lf + rf . if Tm = k2 . if Tm = j + f . ω eb = k3 . ω Dimana: r 1. ea = k4 . r 2. k1(ea – eb) = ef Ea = k4 . R Ef = k1(Ea – Eb) Ef = LsIf + Rf .If Tm = k2 . If Tm = JΩs + f.Ω Eb = k3 . ω 3. L ef = Lf + rf . if 4. Tm= k2 . if ΣT = j . α Tm = j + f . ω
Ef = Lf Ef Ea Ω If R K2/Js+f 1/Ls+Rf K1 K4 R Ω Eb K3 Ω R 20 0,1 DC Motor Speed Modeling Diagram Blok Asumsi: Ea = k4 . R Eb = k3 . Ω
R Ω Respon Transien Analisis t
S1,2 = R Ω Root Locus Analisis 1. Pole (k=0) 1 + GH = 0 S2 + 14,5 S + 150 = 0 S1,2 = S1 = -7,25 + 9,87 i S2 = -7,25 – 9,87 I Np=2 90° -7,25 + 9,87i -7,25 2. Zero (k=~) Zero tidak ada Nz = 0 -7,25 - 9,87i 3. Asimtot. σ = = -7,25 = = ±90
Reference http://www.engin.umich.edu/group/ctm/examples/motor/PID2.html . Di akses 3/5/10 Ogata, katsuhiko. Modern Control Engineering. 4 edition Kreyszig. Advanced Engineering Mathematics. 9 edition erima Kasih
INK: • DC Motor Speed Modeling • Diagram Blok ertanyaan? • Respon Transien Analisis • Root Locus Analisis