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1. Petroleum Engineering 406Lesson 18 Directional Drilling
3. Homework: READ. “Applied Drilling Engineering” Ch. 8, pp. 351-363
REF. API Bulletin D20, “Directional Drilling Survey Calculation Methods and Terminology”
4. What is Directional Drilling? Directional Drilling is the process of directing a wellbore along some trajectory to a predetermined target.
Basically it refers to drilling in a non-vertical direction. Even “vertical” hole sometimes require directional drilling techniques.
14. Build Section:
17. Fig. 8-14. Directional well used to intersect multiple targets
18. Fig. 8-15. Directional quadrants and
compass measurements
20. Example 1: Design of Directional Well Design a directional well with the following restrictions:
Total horizontal departure = 4,500 ft
True vertical depth (TVD) = 12,500 ft
Depth to kickoff point (KOP) = 2,500 ft
Rate of build of hole angle = 1.5 deg/100 ft
21. Example 1: Design of Directional Well This is a Type I well (build and hold)
(i) Determine the maximum hole angle (inclination) required.
(ii) What is the total measured depth of the hole (MD)?
25. Solution Type I Well 1.5 deg/100’
26. Build Section MD1 = 1,800’ (27/1.5)
TVD1 = 1,734’
HD1 = 416’
Remaining vertical height
= 10,000 - 1,734 = 8,266’
27. Solution Horizontally:
416 + 8,266 tan 27o = 4,628
We need 4,500’ only:
Next try Imax = 25’ 30 min
28. Solution: Remaining vertical depth = 10,000-1644
= 8,356 ft.
? Horizontal deviation = 372+8,356 tan 25.5
= 4,358 ft. { ?4500 }
Approx. maximum angle = 26
What is the size of target?
29. MD = MDvert + MDbuild + MDhold
30. Type II Pattern Given: KOP = 2,000 feet
TVD = 10,000 feet
Horiz. Depart. = 2,258 feet
Build Rate = 20 per 100 feet
Drop Rate = 10 30’ per 100 feet
The first part of the calculation is the same as previously described.
31. Procedure - Find: a) The usable depth (8,000 feet)
b) Maximum angle at completion of buildup (180)
c) Measured depth and vertical depth at completion of build up (M.D.=900 ft. and TVD = 886)
d) Measured depth, horizontal departure and TVD for 1 /100 ft from chart.
32. Solve: For the distances corresponding to the sides of the triangle in the middle.
Add up the results.
If not close enough, try a different value for the maximum inclination angle, Imax
33. Example 1: Design of Directional Well (i) Determine the maximum hole angle required.
(ii) What is the total measured depth (MD)?
(MD = well depth measured along the wellbore,
not the vertical depth)
34. (i) Maximum Inclination Angle
35. (i) Maximum Inclination Angle
36. (ii) Measured Depth of Well
37. (ii) Measured Depth of Well
38. We may plan a 2-D well, but we always get a 3D well (not all in one plane)
39. Fig. 8-22. A curve representing a wellbore between survey stations A1 and A2
40. Directional Drilling 1. Drill the vertical (upper) section of the hole.
2. Select the proper tools for kicking off to a non-vertical direction
3. Build angle gradually
41. Directional Tools (i) Whipstock
(ii) Jet Bits
(iii) Downhole motor and bent sub
42. Whipstocks
43. Setting a Whipstock Small bit used to start
Apply weight to:
set chisel point &
shear pin
Drill 12’-20’
Remove whipstock
Enlarge hole
44. Jetting Bit Fast and economical
For soft formation
One large - two small nozzles
Orient large nozzle
Spud periodically
No rotation at first
45. Jetting Wash out pocket
Return to normal drilling
Survey
Repeat for more angle if needed
46. Mud Motors
48. Increasing Inclination Limber assembly
Near bit stabilizer
Weight on bit forces DC to bend to low side of hole.
Bit face kicks up
49. Hold Inclination Packed hole assembly
Stiff assembly
Control bit weight and RPM
50. Decrease Inclination Pendulum effect
Gravity pulls bit downward
No near bit stabilizer
51. Packed Hole Assemblies
54. Deflecting Wellbore Trajectory
55. Bottom Hole Location
56. Survey Calculation Methods 1. Tangential Method
= Backward Station Method
= Terminal Angle Method
Assumption: Hole will maintain constant inclination and azimuth angles between survey points
58. Average Angle Method = Angle Averaging Method Assumption: Borehole is parallel to the simple average drift and bearing angles between any two stations.
Known: Location of A, Distance AB,
Angles
59. (i) Simple enough for field use
(ii) Much more accurate than
“Tangential” Method
60. Average Angle Method
Vertical Plane:
61. Average Angle Method
Horizontal Plane:
62. Change in position towards the east:
Change in position towards the north:
63. Example The coordinates of a point in a wellbore are:
x = 1000 ft (easting)
y = 2000 ft (northing)
z = 3000 ft (depth)
At this point (station) a wellbore survey shows that the inclination is 15 degrees from vertical, and the direction is 45 degrees east of north. The measured distance between this station and the next is 300 ft….
64. Example The coordinates of point 1 are:
x1 = 1000 ft (easting)
y1 = 2000 ft (northing) I1 = 15o
z1 = 3000 ft (depth) A1 = 45o
L12 = 300 ft
At point 2, I2 = 25o and A2 = 65o
Find x2 , y2 and z2
65. Solution H12 = L12 sin Iavg = 300 sin 20 = 103 ft
DE = H12 sin Aavg = 103 sin 55 = 84 ft
DN = H12 cos Aavg = 103 cos 55 = 59 ft
DZ = L12 cos Iavg = 300 cos 20 = 282 ft
66. Solution - cont’d DE = 84 ft
DN = 59 ft
DZ = 282 ft
x2 = x1 + DE = 1,000 + 84 ft = 1,084 ft
y2 = y1 + DN = 2,000 + 59 ft = 2,059 ft
z2 = z1 + DZ = 3,000 + 282 ft = 3,282 ft