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Oxidation- Loss of Electrons Reduction-Gain of Electrons. Ionization Energy- Is the energy required to remove an electron. Big Idea 1 (Atomic Structure) Chemical elements are fundamental building materials
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Oxidation- Loss of Electrons Reduction-Gain of Electrons Ionization Energy- Is the energy required to remove an electron.
Big Idea 1 (Atomic Structure) Chemical elements are fundamental building materials of matter, and all matter can be understood in terms of arrangements of atoms. These atoms retain their identity in chemical reactions.
Big Idea 2 (Bonding&IMF) Chemical and physical properties of materials can be explained by the structure and the arrangement of atoms, ions, or molecules and the forces between them.
Big Idea 3 (Reactions) Changes in matter involve the rearrangement and/or reorganization of atoms and/or the transfer of electron.(Electrochem)
Big Idea 4 (Kinetics) Rates of chemical reactions are determined by details of the molecular collisions.
Big Idea 5 (Thermochem) The laws of thermodynamics describe the essential role of energy and explain and predict the direction of changes in matter.
Big Idea 6 (Equilibrium) Any bond or intermolecular attraction that can be formed can be broken. These two processes are in a dynamic competition, sensitive to initial conditions and external perturbation.
Science Practice 1: The student can use representations and models to communicate scientific phenomena and solve scientific problems. Science Practice 2: The student can use mathematics appropriately. Science Practice 3: The student can engage in scientific questioning to extend thinking or to guide investigations within the context of the AP course. Science Practice 4: The student can plan and implement data collection strategies in relation to a particular scientific question. Science Practice 5: The student can perform data analysis and evaluation of evidence. Science Practice 6: The student can work with scientific explanations and theories.
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Unit 1 Chemical Foundations
The termquantitativedata represent various observations or measurements that are numerical. Some examples include: * Mass * Density * Average Volume * Boiling Point The termqualitativedata refers to observations that are descriptive. Some examples include: * Color * Texture * Odor
Law of Definite Proportions : (chemistry) law stating that every pure substance always contains the same elements combined in the same proportions by weight .
1. Complete combustion of a sample of a hydrocarbon in excess oxygen produces equimolar quantities of carbon dioxide and water. Which of the following could be the molecular formula of the compound? a. C2H2 b. C2H6 c. C4H8 d. C6H6
The natural abundance for boron isotopes is: 19.9% 10B (10.013 amu) and 80.1% 11B (11.009amu). Calculate the atomic atomic mass of boron.
Law of Multiple Proportions When two elements combine to form two or more compounds, the ratio formed from each compound’s mass ratio always yields a fraction. Elements can only combine in specific combinations. They must be whole numbers. Ex. Consider two compounds of Sulfur and Oxygen Compound A has a mass composition of 49.9% O and 50.1% S Compound B has a mass composition of 59.9% O and 40.1% S Answer: Big Idea One p. 17
Filtration is commonly the mechanical or physical operation which is used for the separation of solids from fluids.
distillation is a method of separatingmixtures based on differences in boiling points of liquid mixtures.
Floatation Flotation is a process of separating mixtures which involves separating substances by whether they sink or float
Identify the number of significant figures: 7.09 x 10¯ 91,600 0.003005 3.200 x 10 250 780,000,000 0.0101 0.00800 5 9 23.1 + 4.77 + 125.39 + 3.581 (3.4617 ) ÷ (5.61)
Naming and writing Compounds Memorize your Polyatomic ions!
Write the formulas for the following compounds. Barium Phosphate Copper I Acetate DinitrogenPentaoxide Hydrogen Permanganate Ammonium Oxalate Iron III Nitrate
Mole Concept Percent composition Empirical formulas
3. The mass percent of carbon in pure glucose, C6H12O6, is 40%. A chemist analyzes an impure sample of glucose and determines that the mass percent of carbon is 38.2%. Which of the following impurities could account for the low mass percent of carbon in the sample? Water Ribose Fructose Sucrose
Calculate the percent composition of carbon in carbon dioxide CO2 Molar mass of compound: Mass due to carbon: 12.01 g/mol Percent composition of carbon: