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opgave 47 a opp beeld = 8 · opp origineel dus k = √8. lengte vergroting = √8 · 15 ≈ 42,4 cm

opgave 47 a opp beeld = 8 · opp origineel dus k = √8. lengte vergroting = √8 · 15 ≈ 42,4 cm breedte vergroting = √8 · 10 ≈ 28,3 cm b opp beeld = 12 · opp origineel dus k = √12. lengte vergroting = √12 · 15 ≈ 52,0 cm breedte vergroting = √12 · 10 ≈ 34,6 cm

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opgave 47 a opp beeld = 8 · opp origineel dus k = √8. lengte vergroting = √8 · 15 ≈ 42,4 cm

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  1. opgave 47 a opp beeld = 8 · opp origineel dus k = √8. lengte vergroting = √8 · 15 ≈ 42,4 cm breedte vergroting = √8 · 10 ≈ 28,3 cm b opp beeld = 12 · opp origineel dus k = √12. lengte vergroting = √12 · 15 ≈ 52,0 cm breedte vergroting = √12 · 10 ≈ 34,6 cm ck = = = 1 opp origineel = 15 · 10 = 150 cm2 opp vergroting = k2 · opp origineel opp vergroting = (1)2 · 150 ≈ 417 cm2 lengte vergroting lengte origineel 25 15

  2. opgave 52 Vat I is origineel en vat II is beeld. ak = 1,8 inhoud II = 1,83· inhoud I inhoud II = 1,83· 45 = 262,44 dm3 ≈ 262 liter. bk = 1,8 opp bodem II = 1,82· opp bodem I opp bodem II = 1,82· 10 = 32,4 dm2. ck = 1,8 hoogte bodem II = 1,8 · hoogte I hoogte bodem II = 1,8 · 4,5 = 8,1 dm.

  3. opgave 57 a Tube II is origineel en tube III is beeld. k = = = 0,75 b inhoud tube III = 0,753· inhoud tube II inhoud tube III = 0,753· 45 ≈ 18,98 cm3 inhoud tube III = 19 ml c Tube II is origineel en tube I is beeld. k = = = 1,25 inhoud tube I = 1,253 · inhoud tube II inhoud tube I = 1,253 · 45 ≈ 87,89 cm3 ≈ 88 ml dk = 1,25 (zie c) opp tube I = 1,252 · opp tube II opp tube I = 1,252 · 60 = 93,75 cm2. lengte tube III lengte tube II 9 12 lengte tube I lengte tube II 15 12

  4. opgave 61 a inhoud schaal II = = =  keer inhoud schaal I, dus k = ≈ 0,9. b opp bodem schaal II = k2 · opp bodem schaal I opp bodem schaal II = · 141,3 ≈ 107,8 cm2 1,6 2,4 6 24

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