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Konstrukce trojúhelníku pomocí Thaletovy kružnice

Konstrukce trojúhelníku pomocí Thaletovy kružnice. ∆ABC: c = 8 cm, v a = 7 cm, a = 60°. Rozbor:. X. C. a. l. b. •. 7. a. A. 8. B. c. S. t. Konstrukce:. •. X. Postup konstrukce: c, │ AB │ = 8 cm S; S = A — B t, t(S, r = 4 cm) l;l (A; r = 7 cm)

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Konstrukce trojúhelníku pomocí Thaletovy kružnice

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  1. Konstrukce trojúhelníku pomocí Thaletovy kružnice

  2. ∆ABC: c = 8 cm, va= 7 cm, a = 60° • Rozbor: X C a l b • 7 a A 8 B c S t

  3. Konstrukce: • X • Postup konstrukce: • c, │AB │= 8 cm • S; S = A — B • t, t(S, r = 4 cm) • l;l(A; r = 7 cm) • Pa, {Pa} = t ∩ l • → BPa • a; │<BAX│= 60° • C;{C} = →AX∩ → BPa • ∆ ABC C l Pa A S B t

  4. Závěr: • při daném zadání má úloha jedno řešení

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