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Bell Ringer 4/25/13 Turn in Friday

Bell Ringer 4/25/13 Turn in Friday When the bell rings you should be silent and in your seat working on the bell ringer. Once you finish the bell ringer you should remain silent. Balance the following equations KMnO 4 + C 3 H 5 (OH) 3  K 2 CO 3 + Mn 2 O 3 + CO 2 + H 2 O

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Bell Ringer 4/25/13 Turn in Friday

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  1. Bell Ringer 4/25/13 Turn in Friday When the bell rings you should be silent and in your seat working on the bell ringer. Once you finish the bell ringer you should remain silent. Balance the following equations KMnO4 + C3H5(OH)3 K2CO3 + Mn2O3 + CO2 + H2O Fe2O3 + Al  Al2O3 + Fe

  2. Review 14 KMnO4 + 4 C3H5(OH)3 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O Fe2O3 + 2 Al  Al2O3 + 2 Fe

  3. Clear Target I can describe a exothermic reaction in terms of change in kJ / mol Reaction Energy = Products – Reactants KMnO4 -813.4 kJ/mol C3H5(OH)3 -669.6 kJ/mol K2CO3 -1150.18 kJ/mol Mn2O3 -959 kJ/mol CO2 -343.5 kJ/mol H2O -285.8 kJ/mol

  4. Clear Target I can describe a exothermic reaction in terms of change in kJ / mol Reaction Energy = Products – Reactants Products 7(-1150.18) + 7(-959) + 5(-343.5) + 16(-285.8) = 21,052 kJ / mol

  5. Clear Target I can describe a exothermic reaction in terms of change in kJ / mol Reaction Energy = Products – Reactants Reactants 14(-813.4) + 4(-669.6) = 14,066 kJ / mol

  6. Clear Target I can describe a exothermic reaction in terms of change in kJ / mol Reaction Energy = Products – Reactants Rxn Energy = -21,052 kJ/mol – (-14,066 kJ/mol) = -6986 kJ/mol

  7. Clear Target I can describe a exothermic reaction in terms of change in kJ / mol Reaction Energy = Products – Reactants Rxn Energy = -21,052 kJ/mol – (-14,066 kJ/mol) = -6986 kJ/mol

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