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Pembahasan Matematika Dasar TOENAS 2012-BEASTUDI ETOS. NURUL FIKRI SURABAYA. 46. 47. Sisi Bangun Persegi = 4 + 6 + 3 = 13 Segitiga D memiliki : Alas : 6, Tinggi : 13 – 6 =7 Jadi Luasnya D = 21. 48. 49. 50. 51. 52. 53. 3x + y = 5 x – y = -1
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PembahasanMatematikaDasarTOENAS 2012-BEASTUDI ETOS NURUL FIKRI SURABAYA |http://nurulfikrisurabaya.co.cc|@nf_sby
46. 47. |http://nurulfikrisurabaya.co.cc|@nf_sby
SisiBangunPersegi = 4 + 6 + 3 = 13 Segitiga D memiliki : Alas : 6, Tinggi : 13 – 6 =7 JadiLuasnya D = 21 48. 49. |http://nurulfikrisurabaya.co.cc|@nf_sby
50. 51. |http://nurulfikrisurabaya.co.cc|@nf_sby
52. 53. 3x + y = 5 x – y = -1 4x = 4 x = 1,y=2 2ax + by =-62a.1 + b.2 =-6 a+b=-3 54. SudahJelas, D |http://nurulfikrisurabaya.co.cc|@nf_sby
55. f(x+1) = x -3 f(x+1) = (x+1) – 4 f(x) = x – 4 f-1(x) = x +4 dan g(x) = x2 –2x (f-1 o g)(x)= f-1(g(x)) = f-1(x2 –2x) = x2 –2x +4 • 2011 2012 • L : L 1,05L • P : P 1,2P • Tot : L + P 1,05L+1,2P • 1,05L = 315 L= 300 ribu ; Tot2012= 1,1 Tot2011 • 315 + 1,2P = 1,1 ( 300 + p) p=150 • Jadi Tot =300 +150 = 450 |http://nurulfikrisurabaya.co.cc|@nf_sby
2x – y > 2 (2,2) 57. -2 X + 2y > 6 Nilai maximum di ( 2,2 ), tidakadanilai minimum |http://nurulfikrisurabaya.co.cc|@nf_sby
Barisan geometri : 3 x y → Barisan aritmatika : x y 18 → 2y = 18 + x Subs. → ×3 (2x - 9)(x - 6) = 0 ► x = 6 → 2y = 18 + 6 y = 12 Jadi x.y = 6.12 = 72 |http://nurulfikrisurabaya.co.cc|@nf_sby
59. |B| = (a + c)(-d) – (-c)(b + d) = -ad – cd + bc + cd = -ad + bc = -(ad – bc) |M| = -1 |http://nurulfikrisurabaya.co.cc|@nf_sby
60. A = (1/3)B → B = 3A C = (1/2)B → B = 2C 3A = 2C 6A = 4C Jadi penghasilan A selama 6 bulan sama dengan penghasilan C selama 4 bulan |http://nurulfikrisurabaya.co.cc|@nf_sby
KITA MAJU BERSAMA ALLAH MENUJU MASA DEPAN CEMERLANG http://nurulfikrisurabaya.co.cc Facebook : Nurul Fikri Surabaya Twitter : @nf_sby |http://nurulfikrisurabaya.co.cc|@nf_sby