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Simulation of multiple Q dK2 errors(cont.2)

 =1e-3(for 20cm Q) variable(for FD). Simulation of multiple Q dK2 errors(cont.2). dK2=2 sgn K1  /r (r=10mm, sgn= 1 : random for each Q ). dK2= + 2 K1  /r (r=10mm). dK2= - 2 K1  /r (r=10mm). Example: d FD=5e-4. Corr . It seems OK for d FD=5e-4.

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Simulation of multiple Q dK2 errors(cont.2)

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  1. =1e-3(for 20cm Q) variable(for FD) Simulation of multiple Q dK2 errors(cont.2) dK2=2 sgn K1 /r (r=10mm, sgn=1: random for each Q) dK2=+2 K1 /r (r=10mm) dK2=-2 K1 /r (r=10mm) Example:dFD=5e-4 Corr  It seems OK for dFD=5e-4.

  2. dK2=2 sgn K1 /r Sin[q], dSK2=2 sgn K1 /r Cos[q] (r=10mm, sgn=1: random for each Q,0<q<2p:uniformly random) Simulation of multiple Q dK2 errors(cont.3) Correction: roll(1mrad step) of SX+K2(1% step) of SX dFD=1e-4 After cor., sy(95%CL)=44nm Iteration of correction x2  sy(95%CL)=47nm Iteration of cor. is not effective Cor.  dFD=5e-4, d20cmQ=5e-4 After cor., sy(95%CL)=225nm SK2 of FD affects significantly to sy. Tolerance of SK2 should be much less than 1e-4. Cor. 

  3. M.Woodley

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