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Standard for riprap and conduit outlet protection. Lets look at an example: Q 25 = 20.00 cfs, W O = 24 Inch or 2.00 ft. T W = 0.2 x D O =0.2 x 2.0 ft.= 0.40 ft., q =20.00 cfs / 2.00 ft. = 10.00 sfs
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Lets look at an example: Q25 = 20.00 cfs, WO = 24 Inch or 2.00 ft. TW = 0.2 x DO =0.2 x 2.0 ft.= 0.40 ft., q =20.00 cfs / 2.00 ft. = 10.00 sfs Old Equation: D50 = 0.016 x q1.33 =0.016 x 10.001.33 = 0.855 ft. TW 0.40 ft. New Equation: D50 = 0.020x q1.33 =0.020x 10.001.33 = 1.069 ft. TW 0.40 ft. 1.069 ft. = 1.25 = 25% Increase in D50 0.855 ft. How much of a difference does this change make ?
Preformed scour hole section has been rearranged to “flow” more logically
Horizontal apron section has been rearranged to “flow” more logically DO 0.5
Ishbash equation Vc is not the velocity correlated with Minimum Specific Energy !
Figure TS14C–6 Graphical solution for Isbash technique for different stone density