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REDOKS DAN ELEKTROKIMIA

REDOKS DAN ELEKTROKIMIA. KONSEP REDOKS : KONSEP OKSIGEN a. Oksidasi = reaksi pengikatan Oksigen C + O 2  CO 2 2Mg + O 2  2MgO 4Al + 3O 2  2Al 2 O 3 b. Reduksi = reaksi pelepasan / pengurangan Oksigen CuO + H 2  Cu + H 2 O

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REDOKS DAN ELEKTROKIMIA

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  1. REDOKS DAN ELEKTROKIMIA KONSEP REDOKS : KONSEP OKSIGEN a. Oksidasi = reaksipengikatanOksigen C + O2 CO2 2Mg + O2  2MgO 4Al + 3O2 2Al2O3 b. Reduksi = reaksipelepasan/penguranganOksigen CuO + H2 Cu + H2O Fe2O3 + 3CO  2Fe + 3CO2 KONSEP ELEKTRON a. Oksidasi = reaksipelepasanelektron Na  Na+ + e Mg  Mg2+ + 2e Al  Al3+ + 3e

  2. REDOKS DAN ELEKTROKIMIA b. Reduksi = reaksipengikatanelektron Cl + e  Cl- O + 2e  O2- 3. KONSEP BILANGAN OKSIDASI (BILOKS) a. Oksidasi = reaksi yang mengalamipeningkatanbiloks b. Reduksi = reaksiygmengalamipenguranganbiloks. BIL. OKSIDASI (TINGKAT OKSIDASI) : Bilanganbulatpositifataunegatif yang menyatakanjmlmuatanygdisumbangkanpadamolekul, ion ataugugus ion yang dibentuknya.

  3. ATURAN BILOKS. Biloksunsurbebas = 0 (nol) Unsurbebas : unsurygberdirisendiri a. mono atomik : C, Si, dansemualogam b. diatomik : O2, N2, H2, F2, Cl2, Br2, dan I2 c. Poliatomik : O3 (ozon), P4, S8dll. 2. Jml total bilokssenyawa = 0 (nol) 3. Jml total bilokssuatu ion = muatannya 4. Biloksunsurgol IA dlmsenyawaselalu = +1 Biloksunsurgol IIA dlmsenyawaselalu = +2 5. Biloksunsurgol. VIA dalamsenyawa = -2 Biloksunsurgol. VIIA dlmsenyawabinerselalu = -1 6. Biloks. UnsurHidrogendlmsenyawa = +1 7. To be continued

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