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SEGITIGA

copy right  Mediane Matematika http://medianematematika.blogspot.com. SEGITIGA. copy right  Mediane Matematika http://medianematematika.blogspot.com.

darius-maynard
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SEGITIGA

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  1. copy right  MedianeMatematika http://medianematematika.blogspot.com SEGITIGA

  2. copy right  MedianeMatematika http://medianematematika.blogspot.com Taman sebuahkotaberbentuksegitiga. Panjangsisitamantersebutadalah 4000 m, 500 m, dan 600 m. PadahariMinggupagi yang cerahArmanberolahragalaripagi mengelilingitaman. JikaArmanberlarimengelilingitamansebanyaktiga kali, berapa meter jarak yang ditempuhnya? Permasalahandiatasdapatkamuselesaikandengankonsepsegitiga.

  3. copy right  MedianeMatematika http://medianematematika.blogspot.com KelilingSegitiga Kelilingsuatubangundataradalahjumlahsisi-sisi yang membatasibanguntersebut. Sehinggauntukmencarikelilingsegitiga, kitahanyaperlumenjumlahkanpanjangketigasisinya. MisalkelilingadalahK, maka A b c c K = + + a b C B a

  4. copy right  MedianeMatematika http://medianematematika.blogspot.com LuasSegitiga Luassegitigadapatdiperolehdenganrumusluaspersegipanjang. C Luaspersegipanjangadalah L = p  l = 7 x 4 = 28 cm2 D l = 4 cm Tarikgarisdarititik B ketitik D sehinggamembagipersegipanjangmenjadi 2 bagian B A Luassegitigaadalah L = ½  28 = 14 cm2 = ½  (74) = 14 cm2 t P = 7 cm a Jikasisimendatardisebut alas (a), sisitegakdisebuttinggi (t), danluassegitigasebagai L L = ½ ×a × t Makarumusluassegitigaadalah

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