1 / 7

Tugas mekanika fluida Amalia septiani

Tugas mekanika fluida Amalia septiani. 20110110058 Teknik sipil Universitas muhammadiyah yogyakarta. Soal dan penyelesaian.

devlin
Download Presentation

Tugas mekanika fluida Amalia septiani

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. TugasmekanikafluidaAmaliaseptiani 20110110058 Tekniksipil Universitasmuhammadiyahyogyakarta

  2. Soaldanpenyelesaian • 1. air mengalirdidalampipaberdiameter 25 cm dengankecepatan 1m/d. padaujungpipatersebutterdapatpipadegan diameter 50 cm. berapakahkecepataaliranpadaujungtersebut ?

  3. penyelesaian Diameter pipa= 25 cm =0,25m Luastampangpipa =A1 = ¼ π DxD = ¼ π (0,25)x(0,25) = 0,0490 m² Diameter pipa= 50cm=0,5m Luastampangpipa =A2= 1/4 3,14 (0,5) (0,5) = 0,1963 Kecepatanaliran = v1 =1m/d Debit aliran = Q = A1xV1= 0,0490 m² Ditanyakan v2 ?

  4. A1xV1 = A2xV2 ¼ π D1² V1 = ¼ π D2² V2 ¼ 3,14 (0,5)² (1) = ¼ 3,14 V2 V2 = 0,0490 : 0,1963 = 0,249 m/d

  5. 2. Suatufluidamengalirmelaluisebuahpipaberjari-jari 6 cm dengankecepatan 4 m/s. Berapakah debit fluidatersebutdinyatakandalam m3/s dan m3/jam?

  6. r = 6 cm = 6 x 10-2 mv = 4 m/sDitanya: Q dalam m3/s dan m3/jam?Jawab:Q = v AA = πr2 = π(6 x 10-2 m)2= 0,0113 m2

  7. Sehingga,Q = v A= 4 m/s . 0,0113 m2= 0,045 m3/sSedangkan dalam satuan m3/jam:Q=(0,045m^3)/1s=(0,045m^3)/(1×1/3600 jam)=162 m^3/jam

More Related