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TUGAS MEKANIKA FLUIDA

TUGAS MEKANIKA FLUIDA. OLEH : DIAN WIRAADIGUNA NIM : 20110110052. JURUSAN TEKNIK SIPIL FAKULTAS TEKNIK UNIVERSITAS MUHAMMADIYAH YOGYAKARTA 2011. SOAL 1. A= 56 m². Q 2. A= 25 m² V= 2 m/s. Q 1. A= 45 m² V=1 m/s. Q 3.

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TUGAS MEKANIKA FLUIDA

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  1. TUGAS MEKANIKA FLUIDA OLEH : DIAN WIRAADIGUNA NIM : 20110110052 JURUSAN TEKNIK SIPIL FAKULTAS TEKNIK UNIVERSITAS MUHAMMADIYAH YOGYAKARTA 2011

  2. SOAL 1 A=56 m² Q2 A=25 m² V= 2 m/s Q1 A=45 m² V=1 m/s Q3 Air mengalirdaripipa 1,2,3. Apabila air mengalirdaripipa 1 denganluas alas 25 m² dankecepatan 2 m/s danpipaitubercabangsepertigamabardiatasdenganpipa 2 luaslasanya 56 m² danpipa 3 luas alas 45 m² dankecepatanya 1 m/s.Berapakecepatandipipa 2?

  3. SOAL 2 A=23m² Q3 A=35m² V=2m/s A=45m² Q1 Q2 Q4=56m³/s Air mengalirdaripipa1,2,3 dan 4 sepertigamabardiatashitunglah Q1, V1,Q2,Q3,V3 ?

  4. SOAL 3 A=25m² V=2m/s Q3 A=67 m² Q1 A=24m² Q2=1/3Q3 Dari gambardiatasberapa debit air di Q1dan Q2sertacarikecepatandiQ1dan Q2 ?

  5. PENYELESAIAN SOAL 1 Dik: A1=25 m² A3=45 m² V2=2m/s V3=1m/s A2=56 m² V2=? Dit: V2? Jawab : Q1=Q2+Q3 A1xV2=A2xV2+A3xV3 25x2=56xV2+45x1 50=56V2+45 56V2=50-45 V2=5/56 V2=0.0893m/s

  6. PENYELESAIN SOAL 2 Dik: A1=45 m² Q4=56m³/s A2=35m² V2=2m/s A3=23m² Dit : Q1,V1,Q2.Q3,V3? Jawab: Q1=Q2 Q2=Q3+Q4 Q3=A3xV3 A1xV1=A2xV2 35x2=A3xV3+Q4 Q3=23x0.086 45V1=35x2 70=23V3+56 Q3=14m³/s V1=70/45 23V3=70-56 V1=1.556m/s V3=0.6086m/s Q1=45x1.556=70m³/s Q2=70m³/s

  7. PENYELESAIAN SOAL 3 Dik : A1=67m² Q2=1/3Q3 A3=25m² V3=2m/s A2=24m² Dit :Q1,Q2,V1 dan V2? Jawab: Q1=Q2+Q3 67V1=1.334x50 Q1=67x0.9950 A1xV1=A2xV2+A3xV3 V1=66.67/67 Q1=66.665m³/s 67V1=1/3Q3+Q3 V1=0.9950m/s 67V1=1.334Q3 Q2=A2xV2 Q3=A3xV3 16.667=24V2 Q3=25x2 V2=0.6944m/s Q3=50m³/s

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