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F.7 Organic Chemistry

F.7 Organic Chemistry. IR Spectroscopy. Relationship between Frequency, Wavelength and Wavenumber c =  where c = velocity of light (ms -1 )  = frequency (Hz or s -1 )  = wavelength (m).

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F.7 Organic Chemistry

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  1. F.7 Organic Chemistry

  2. IR Spectroscopy

  3. Relationship between Frequency, Wavelength and Wavenumberc =  where c = velocity of light (ms-1) = frequency (Hz or s-1) = wavelength (m)

  4. LIMITATIONS OF THE USE OF IR SPECTROSCOPY IN THE IDENTIFICATION OF ORGANIC COMPOUNDS1. Some infrared absorptions have very close wavenumbers and the peaks overlap with each other .2. NOT all vibrations give rise to strong absorption peaks. 3. Intermolecular interactions (such as H-bond) between molecules complicate infrared spectra.4. Infrared spectroscopy can only provide limited structural information of molecules.

  5. Correlation Table of Functional Groups and IR Absorption Wavenumbers

  6. Correlation Table of Functional Groups and IR Absorption Wavenumbers

  7. Examples of some IR Spectra

  8. CH2=CHCHCCH3 O C=C C=O

  9. CH3(CH2)3CCH CC

  10. CH3CO(CH2)3CH3 O C=O

  11. CH3C-C-CH3 H3C O C=O

  12. CH3(CH2)3NH2 e.g. Butylamine N-H

  13. CH3CH2CN C=N

  14. For more examples on the internet, please click the following buttons. IR Spectrometer and other Apparatus Spectra of some organic and inorganic compounds

  15. Movie: To run an IR spectrum in the Laboratory Please press this button if you want to see the movie. 

  16. Exercise on IR Spectroscopy Explain how you distinguish between each isomer in the following pairs of compounds by infrared absorption peaks. a. H2CCHCH2OH and (CH3)2C=O b. HCCCH2CH2CH3 and H2C=CHCH2CH=CH2 c. CH3CH2CH2NH2 and (CH3)2N Press this button for solutions 

  17. alam: a. H2CCH CH2OH and (CH3)2C=Ob.HCCCH2CH2CH3and H2C=CHCH2CH=CH2c. CH3CH2CH2NH2 and (CH3)2N 1610 cm-1 3300 cm-1 1700 cm-1 2120 cm-1 1610 cm-1 1610 cm-1 No 3400 cm-1 3400 cm-1

  18. The END

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