1 / 2

273. lpp uzdevums 9

273. lpp uzdevums 9. Dots: Trijstūra prizma ABCA 1 B 1 C 1 S(AA 1 MK) = 72 – šķēlums AB = 17; AC = 10; BC = 21. Jāaprēķina: augstums MK -? Atrisinājums: BK = x, CK = 21 – x, Tad AK 2 = AB 2 –BK 2 AK 2 = AC 2 – CK 2 AB 2 –BK 2 = AC 2 – CK 2. B 1. M. A 1. C 1.

forrest-marshall
Download Presentation

273. lpp uzdevums 9

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 273. lppuzdevums 9 Dots: Trijstūra prizma ABCA1B1C1 S(AA1MK) = 72 – šķēlums AB = 17; AC = 10; BC = 21. Jāaprēķina: augstums MK -? Atrisinājums: BK = x, CK = 21 – x, Tad AK2 = AB2 –BK2 AK2 = AC2 – CK2 AB2 –BK2 = AC2 – CK2 B1 M A1 C1 Taisnas trijstūra prizmas pamata malu garumi ir 10,17, 21. Šķēluma, kas iet caur sānu šķautni un pamata mazāko augstumu, laukums ir 72. Aprēķini prizmas augstumu. B x K 21 - x A C - Pēc Pitagora teor.

  2. 172 – x2 = 102 - (21-x)2 289 - x 2 = 100 – (441 – 42x + x2) 289 – x2 = 100 – 441 + 42x – x2 - 42 x = - 630 x = 15, BK = 15 Pēc Pitagora teorēmas: AK2 = AB2 – BK2 = 172 – 152= = 289 – 225 = 64 AK = 8 Tā kā AA1MK ir taisnstūris S(taisnstūris) = ab =>MK= = = =9 Atbilde: Prizmas augstums MK = 9 S (AA1MK) 72 8 AK

More Related