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Penerapan

Indikator. Apersepsi. Contoh. Latihan. Penerapan. Teorema Pythagoras. Pada Bangun Datar. KOMPETENSI DASAR : Memecahkan masalah pada bangun datar yang berkaitan dengan teorema pythagoras. STANDAR KOMPETENSI

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Penerapan

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  1. Indikator Apersepsi Contoh Latihan Penerapan Teorema Pythagoras Pada Bangun Datar

  2. KOMPETENSI DASAR : Memecahkanmasalahpadabangundatar yang berkaitandenganteoremapythagoras STANDAR KOMPETENSI • Menggunakanteoremapythagorasuntukmenyelesaikansoal yang berkaitandenganbangundatar INDIKATOR • Menghitungpanjang diagonal bangundatar. • Menghitungpanjangsisibangundatar. • Menghitungkelilingdanluasbangundatar. Kembali ke Menu Lanjut

  3. Apersepsi L = s2 K = 4s Persegi s Persegi panjang l K = 2(p+l) L = p x l p Jajar genjang t b L = a x t K = 2(a + b) a

  4. Apersepsi Belah Ketupat L = ½ d1 x d2 K = 4s s Layang-layang K = 2(a+b) L = ½ d1 x d2 a b b Trape- sium L = ½(a+b)xt d K = a+b+c+d c t a

  5. Contoh 1 Perhatikan gambar persegi di bawah ini. Hitunglah panjang diagonal AC ! Jawab D C BC2 AB2 + AC2 = 62 + AC2 = 62 36 36 + AC2 = 36 x 2 AC2 = A B 6 cm 36x 2 AC = AC = 6 2 2 6 Jadi panjang diagonal AC = cm

  6. Contoh 2 Perhatikan gambar persegipanjang di bawah ini. Hitunglah panjang diagonal AC ! Jawab AC2 = AB2 + BC2 D C 82 + 62 AC2 = 6 cm 36 64 + AC2 = 100 AC2 = B A 8 cm 100 AC = AC = 10 Jadi panjang diagonal AC = 10 cm

  7. Contoh 3 Perhatikan gambar belah ketupat di bawah ini. Jika panjang AC=10cm dan panjang diagonal BD=24cm, hitunglah keliling dan luas belah ketupat! Jawab D d1 d2 x DE2 + EC2 x CD2 = Luas = 122 + 52 CD2 = 12 x 10 24 x = 25 144 + CD2 = C A E 5 x 240 = 169 CD2 = 169 CD= 120 = CD= 13 B Jadi luasnya = 120 cm2 Keliling = 4s = 4(13) = 52 Jadi kelilingnya = 52 cm

  8. LATIHAN SOAL • Hitunglah panjangdiagonal AB dan BC! D C A B

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