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Teorema Bayes

Teorema Bayes. S. B. A. B’. A = (B A) (B’ A) P(A) = P(B A) + P(B’ A) = P(B).P(A │ B) + P(B’).P(A │ B’). Dalil Peluang Total. Jika kejadian-kejadian B i ≠ 0 ; i= 1,2,3,…,k maka untuk sembarang kejadian A yang

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Teorema Bayes

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  1. Teorema Bayes S B A B’ A= (BA) (B’ A) P(A) = P(BA) + P(B’A) = P(B).P(A│B) + P(B’).P(A│B’)

  2. DalilPeluang Total Jikakejadian-kejadian Bi ≠ 0 ; i= 1,2,3,…,k makauntuksembarangkejadian A yang merupakanhimpunanbagian S berlaku: P(A) = P(B1).P(A│B1)+P(B2).P(A│B2)+ ….. + P(Bk).P(A│Bk)

  3. Kaidah Bayes Jikakejadian B1, B2, B3, …, Bkmerupakansekatandariruangcontoh S dengan P(Bi) ≠ 0 untuk i= 1,2,…, k ; makauntuksembarangkejadian A yang bersifat P(A) ≠ 0 : P(Bi│A) = =

  4. Teladan 1 120 S IV 100 30 AS 60 40 I 20 III 80 200 II Diagram Venn untukkejadianmemakaikartuteleponseluler As padasampelmahasiswasetiaptingkat di STIS

  5. Teladan 2 Suaturestoran pizza menyediakanbahandasarutamadalamtopping pizza dengankomposisidaging 60%, ayam 30% dansisanyaikan. Bila 20% dalam toping dasarutamadaging, 10% dalam toping dasarayamdan 5% dalam toping dasarikanselaluterdapatkejumozarella, hitunglahpeluangbahwa: a. seorang yang memesan pizza mendapatkeju mozarella b. seorang yang memesan pizza mendapatkeju mozarellaternyatamemilih toping dasarayam

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